9.1.7 Checkerboard V2 Answers !!install!! Guide

You need to create an 8x8 grid (a list of lists) where the elements alternate between 0 and 1 . The key constraint is often that you must use nested loops and assignment statements ( board[i][j] = 1 ) rather than just printing the expected output string. The Solution: Python Implementation

This ensures that no two adjacent squares (horizontal or vertical) have the same value. Common Pitfalls

: In Python, improper indentation of your nested loops will cause a SyntaxError or logic failure. Ensure your if statement is inside the second loop. 9.1.7 checkerboard v2 answers

The logic (row + col) % 2 != 0 is the standard mathematical way to create a checkerboard. : Sum is 0 (Even) → stays 0 . Row 0, Col 1 : Sum is 1 (Odd) → becomes 1 . Row 1, Col 0 : Sum is 1 (Odd) → becomes 1 . Row 1, Col 1 : Sum is 2 (Even) → stays 0 .

# Function to print the board in a readable format def print_board(board): for row in board: print(" ".join([str(x) for x in row])) # 1. Initialize an 8x8 grid filled with 0s board = [] for i in range(8): board.append([0] * 8) # 2. Use nested loops to apply the checkerboard pattern for row in range(8): for col in range(8): # If the sum of row + col is odd, set the value to 1 # This creates the alternating pattern if (row + col) % 2 != 0: board[row][col] = 1 # 3. Output the result print_board(board) Use code with caution. Why This Works You need to create an 8x8 grid (a

For more practice on similar grid-based logic, you can explore the CodeHS Python Curriculum which covers 2D lists and nested iterations in detail.

The exercise is a common challenge in introductory Python courses, specifically on platforms like CodeHS . While version 1 typically asks you to fill specific rows with 1s, version 2 requires a true alternating checkerboard pattern across the entire 8x8 grid. The Objective Common Pitfalls : In Python, improper indentation of

: Ensure your loops run exactly range(8) to match the 8x8 requirement.